Question

The average of first 50 natural numbers is …………. .

Answer 1

$\bold{Answer :}$

The first 50 natural numbers are

1, 2, 3, ..., 50

So, the 1st term (a₁) = 1,

the last term (a₅₀) = 50

Then, the sum of 1st n = 50 natural numbers be

= n/2 * (a₁ + a₅₀)

= 50/2 * (1 + 50)

= 25 * 51

= 1275

Hence, the average of 1st 50 natural numbers be

= 1275/50

= 25.5

#$\bold{MarkAsBrainliest}$

Answer 2

Heya !!

First 50 natural numbers are : 1 , 2 , 3.....50

Here,

First term ( A ) = 1

Common difference ( D ) = 1

Sn = N/2 × [ 2A + ( N - 1 ) × D ]

S50 = 50/2 × [ 2 × 1 + ( 50 - 1 ) × 1 ]

=> 25 × ( 2 + 49 )

=> 25 × 51

=> 1275.



Average = 1275/50 = 25.5