Question

The average of first five multiples of 3 is:
A.9
B.10
C.8
D.11

Answer 1

First 5 multiple of 3 are :

3,6,9,12,15

Their sum = 3 + 6 + 9 + 12 + 15

Sum = 45

Average = sum of observations /no of observations.

Average = 45/5

Average = 9

Hence avg of first five multiples is 9.

So option :A. 9

Answer 2

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First five multiples of 3 = 3,6,9,12,15

Now,
$average = \frac{sum \: of \: all \: observations}{number \: of \: observations}$
$= \frac{3 + 6 + 9 + 12 + 15}{5} \\ = \frac{45}{5} \\ = 9$

So, Average of five five multiples of 3 is:

Option (A) - 9

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