Question

The average of first 'n' natural number is

Answer 1

Answer:

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Step-by-step explanation:

The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4.

Answer 2

Answer:

(n+1)/2

Step-by-step explanation:

Sum=n(n+1)/2