Question

The average of five consecutive even no.Is 26 ,find th product of first or last number

Answer 1

Answer:

$numbers \: = > \\ \\ x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 26 \\ \\ 5x + 10 = 26 \\ \\ x = \frac{16}{5 } \\ \\ multiply \: \: = > (x)(x + 4) = \frac{16}{5} ( \frac{36}{5} ) \\ \\ = \frac{576}{25}$

Answer 2

Given,

Average of 5 consecutive even numbers  = 26

To Find,

Product of first and last number =?

Solution,

Let the first number be x

Numbers are consecutive even numbers which mean that the difference between each number is 2

So 5 number are: x, x+2, x+4, x+6, and x+8

Average of these numbers  = 26 = Sum of all numbers / Total numbers

26 = (x + x + 2 +x + 4 + x + 6 + x + 8)/5

5x + 20 = 26 * 5

5x + 20 = 130

5x = 130 - 20

x = 110 / 5

x = 22

First number is  22

Last number  = x + 8 = 22 + 8 = 30

Product of first and last number  = 30 * 22 = 660

Hence, the product of the first term and last term is 660