The average of five numbers is 496.If two of them are 117 and 140, find the average of remaining three numbers.
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Answered by
20
Let five observations are ; a , b, c, d, and e
given, average = 496
we know, average = sum of observations/total number of observations
496 = (a + b + c + d + e)/5
a + b + c + d + e = 496 × 5 = 2480
a/c to question, two observations are 117 and 140 .
Let a = 117 and b = 140
then, 117 + 140 + c + d + e =2480
c + d + e = 2480 - (117 + 140)
c + d + e = 2480 - 257 = 2223
now, average of remaining three observations
= (c + d + e)/3
= (2223)/3
= 741
given, average = 496
we know, average = sum of observations/total number of observations
496 = (a + b + c + d + e)/5
a + b + c + d + e = 496 × 5 = 2480
a/c to question, two observations are 117 and 140 .
Let a = 117 and b = 140
then, 117 + 140 + c + d + e =2480
c + d + e = 2480 - (117 + 140)
c + d + e = 2480 - 257 = 2223
now, average of remaining three observations
= (c + d + e)/3
= (2223)/3
= 741
Answered by
7
Answer:
Average of the remaining 3 numbers is 741
Step-by-step explanation:
Average
= Sum of the observations / no. of observations
In the attachments I have answered this problem.
See the attachment for detailed solution.
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