The average of four consecutive even numbers is 27. Find the smallest of these numbers.
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Let, the first number be a. So, the consecutive numbers will be a+2, a+4 and a+6.
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According to question,
(a + (a+2) + (a+4) + (a+6))/4 = 27
a + (a+2) + (a+4) + (a+6) = 27*4
4*a + 12 = 27*4
4*a + 4*3 = 4*27
4(a+3) = 4*27
a+3 = 27
a = 24
We have to find largest so the answer is a+6 = 24+6 = 30.
In other way, you can see that 27 is the average that means there are 2 even numbers before it and two after it. As the numbers are consecutive so the numbers are 24, 26, 28 and 30.
Step-by-step explanation:
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