Question

The average of four consecutive numbers, a,b,c and d respectively is 56.5.

Answer 1

Answer:

Step-by-step explanation:

From above question if its average of 4 the

(a+b+c+d)/4 = 56.5

a+b+c+d = 226.0 ...............................(i)

from the question a , b ,c and d are consecutive number than

Let suppose

a= x

b= x+1

c=x+2

d= x+3

so from the equation (i)

a+b+c+d = 226.0

x+x+1+x+2 +x+3= 226

4x+ 6 = 226

4x = 220

x= 55

so than

a=55

b=56

c=57

d =58