The average of four consecutive
numbers A, B, C and D respectively
is 49.5. What is the product of B & D?
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let these numbers are x, x+1, x+2, x+3
so the average = [x+(x+1)+ (x+2) + (x+3)] ÷ 4 = 49.5
do cross multiply so u will get 4x + 6 = 49.5×4
= 4x +6 =196
= 4x = 196 -6
= 4x =192
= x = 192/4
= x = 48
so these numbers are 48, 49, 50, 51
so the product of b and d is = 49× 51 = 2499
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so the average = [x+(x+1)+ (x+2) + (x+3)] ÷ 4 = 49.5
do cross multiply so u will get 4x + 6 = 49.5×4
= 4x +6 =196
= 4x = 196 -6
= 4x =192
= x = 192/4
= x = 48
so these numbers are 48, 49, 50, 51
so the product of b and d is = 49× 51 = 2499
please mark this answer as brainliest and follow me
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