Question

The average of four consecutive numbers A, B, C, D is 55.5. Then, the product BC

Answer 1

let the four consecutive number be = x , x+1,
x+2, x+3
4x + 6 = 55.5 ×4
4x +6 =222
4x = 222- 6
4x = 216
x = 216/4

x= 54

B =x+1 = 54 +1 = 55

C = x+2 = 54 +2 =56
product of BC = 55 ×56 = 3080


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Answer 2

x+x+1+x+2+x+3+x+4=55.5×4=222
4x+6=222
4x=216
x=54
B=55
C=56
BC=55×56=3080
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