Question

The average of four numbers with a difference of 2 between them is ​

Answer 1

Answer:

The average of four numbers is 74 and the difference between the first three numbers is 2, the difference between the third and fourth numbers is 6. What is the value of each number?

5 Answers

Ved Prakash Sharma

, former Lecturer at Sbm Inter College, Rishikesh (1971-2007)

Answered 3 years ago · Author has 10.6K answers and 8.5M answer views

Let first three numbers are n, (n+2) and (n+4). then 4th number is. (n+4+6)=

(n+10) , acordingly:-

n+(n+2)+(n+4)+(n+10)=4×74

or. 4n+16=4×74

or. 4×(n+4) =4×74

or. n+4=74=> n=70

1st No=n=70

2nd No= n+2=70+2=72

3rd No = n+4=70+4=74

4th No= n+10=70=10=80

Thus , the numbers are 70 , 72 , 74 and 80 . Answer.

Another possible -answer:-

Let 1st number is x the 2nd and 3rd are. (x-2) and (x-4) respectively.

4th number is (x-4-6) or (x-10). Acordingly:-

[ (x) +(x-2)+(x-4)+(x-10)] =4×74

or 4x - 16 = 4×74

or. 4×(x-4)= 4×74

or. x-4=74 => x= 78.

1st No = x. = 78

2nd No=x-2=78–2=76

3rd No=x-4=78–4=74

4th No=x-10=78–10= 68

Numbers are 78 , 76 , 74 and 68. Answer.

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