Question

The average of four positive integers is 73.5. The
highest integer is 108 and the lowest integer is 29.
The difference between the remaining two integers
is 15. Which of the following is larger of remaining
2 integers?​

Answer 1

Answer:

Let one integer be x.

Other integer = x + 15

According to the question,

9+x+x+15+108=4×73.5

= 2x + 152 = 294

= 2x = 294 - 152 = 142

x=14242=71

answer