Question

The average of n numbers is 16.
If 5/8th of the

numbers are doubled and 3/8th of the numbers

become 10/3 times their original values, by what

percentage does the current average exceed the

original average?​

Answer 1

Answer:

Step-by-step explanation:

The average of n numbers is 16

so sum =16n

5/8 th of 16 n=16n*(5/8)=10n

Double of this=20n

3/8th of 16n =16n*(3/8)=6n

This becomes 10/3 times =6n*10/3=20n

So sum of new numbers=20n+20n=40n

Hence New avg v=20n/n=20

% increase

=(20-16)*100/16

=400/16

=25%