The average of n numbers is 4n , if n is added to each given number , what will be the new average
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average of n number is 4n
let sum of numbers be X
X÷n=4n
X=4n^2
n is added to given number then sum became
4n^2+n
number of numbers are n+1
average is
=(4n^2+n)÷n+1
let sum of numbers be X
X÷n=4n
X=4n^2
n is added to given number then sum became
4n^2+n
number of numbers are n+1
average is
=(4n^2+n)÷n+1
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