Question

The average of nine consecutive numbers is n. If the next
two numbers are also included, the new average will​

Answer 1

Answer:

n + 1

Step-by-step explanation:

ATQ;

(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8)/9 = n

=> ( 9a + 36)/9 = n

=> a + 4 = n -------------------- ( 1 )

If the next 2 numbers are included , let new average = k

(a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 + a + 6 + a + 7 + a + 8 + a + 9 + a + 10)/11 = k

( 11a + 55)/11 = k

a + 5 = k -------------------- ( 2 )

Subtracting ( 1 ) from ( 2 ) , we get :

a + 5 - a - 4 = k - n

=> k - n = 1

=> k = n + 1

Therefore the new average is n + 1