Question

The average of P.Q.R and S is 37 and that of Q.R.S and T is 41 if T is 3/2 timer of P, then P =?

Answer 1

Step-by-step explanation:

The average of P.Q.R and S is 37 and that of Q.R.S and T is 41 if T is 3/2 timer of P, then P =?

Answer 2

The value of P = 32.

Given,

The average of P.Q.R and S is 37.

The average of Q.R.S and T is 41.

T is 3/2 times of P.

To Find,

The value of P.

Solution,

First, Let's understand the concept of average .

The average is defined as the mean arthmetic value which is equal to the ratio of the sum of the number of a given values to the total number of values present.

average of P.Q.R and S = $\frac{P+Q+R+S}{4}$= 37.

= P+Q+R+S = 37×4 = 148.

average of Q.R.S and T =$\frac{Q+R+S+T}{4}$= 41.

= Q+R+S+T = 41×4 = 164.

On comparing,

P+Q+R+S - 148 = Q+R+S+T - 164.

T-P = 16.

then,

using T is 3/2 times of P,

$\frac{3}{2}$P-P = 16.

$\frac{P}{2}$ = 16.

P = 32.

The value of P = 32.

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