Question

The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?

Answer 1

Gɪᴠᴇɴ :-

• Average Runs of 10 Innings = 32
• Average Has to increased by = 4

Tᴏ Fɪɴᴅ :-

• How many runs must he make in his next innings ?

Sᴏʟᴜᴛɪᴏɴ :-

→ Total Innings played = 10

→ Average score = 32 .

→ Total Score = Average score * Total innings

→ Total Score = 32 * 10

→ Total Score = 320.

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Now,

Let us Assume That, he score X runs in Next inning .

So,

→ Total Innings Now = 10 + 1 = 11

→ Total Runs Now = (320 + X)

→ New Average Now = 32 + 4 = 36 .

Therefore,

→ Average score * Total innings = Total Runs .

→ 36 * 11 = (320 + x)

→ 320 + x = 396

→ x = 396 - 320

→ x = 76 Runs (Ans.)

Hence, The player has to Score 76 Runs in Next innings to Increase His Average by 4.

Answer 2

Aɴꜱᴡᴇʀ

☞ Runs scored = 76 runs

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Gɪᴠᴇɴ

➳ Average run of 10 innings = 32

➳ Average increase by 4 at the end of the next innings

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Tᴏ ꜰɪɴᴅ

➳ Runs taken in the next innings

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Sᴛᴇᴘꜱ

So at the end of 10 innings the batsman would have scored Average score × Total innings

$\large \mapsto{} \tt32 \times 10 \\ \\ \large \tt \mapsto{}320 \: runs$

❍ So then let's assume that he scored X runs in his 11 th innings,then the total score is,

$\large \tt \mapsto{}320 + x \\ \\ \large \tt so \: now \: that \: the \: average \: is \: 36 \\ \\ \boxed{ \tt{}average \: score \times total \: innings = total \: runs} \\ \\ \large \tt \leadsto36 \times 11 = 320 + x \\ \\ \large \tt \leadsto396 - 320 = x \\ \\ \large \tt \pink{ \leadsto{}x = 76}$

Therefore the runs scored in the 11 th innings is 76

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