Question

The average of square of natural number From 1 to 75 is

Answer 1

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Step-by-step explanation:

Sum=n(n+1)/2

Sum=n(n+1)/2and we know that

Sum=n(n+1)/2and we know that Average= sum/number

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/2

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers=n(n+1)

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers=n(n+1)Average of first n even numbers=n+1

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers=n(n+1)Average of first n even numbers=n+14. Sum of the squares of first n natural numbers

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers=n(n+1)Average of first n even numbers=n+14. Sum of the squares of first n natural numbers=n(n+1)(2n+1)/6

Sum=n(n+1)/2and we know that Average= sum/numberso average of first n natural numbers is Average=n(n+1)/2n=(n+1)/22. Sum of first n odd numbers=n²Average of first n odd numbers=n3. Sum of first n even numbers=n(n+1)Average of first n even numbers=n+14. Sum of the squares of first n natural numbers=n(n+1)(2n+1)/6Average =(n+1)(2n+1)/6