Math, asked by akumarthybrothers, 6 months ago

The average of the first eight multiples of 2 is​

Answers

Answered by syed2020ashaels
0

Answer:

Average of first eight multiples of 2 is 11.

Step-by-step explanation:

Element sum=4+6+8+10+12+14+16+18=88

8 elements are present.

sum of elements / total number of elements=88/8=11.

The sum of the first eight multiples of 2 is 11.

Arithmetic Progression (AP) is a number sequence in which the difference between any two consecutive numbers is a constant value. Arithmetic Sequence is another name for it. For example, the natural number sequence 1, 2, 3, 4, 5, 6,... is an Arithmetic Progression with a common difference of one between two successive terms (say 1 and 2). (2 -1). Even in the case of odd and even numbers, the common difference between two consecutive terms is equal to 2.

We come across Arithmetic progression quite frequently in our daily lives. For example, the number of students in a class, the number of days in a week, or the number of months in a year. This pattern of series and sequences has been generalised as progressions in mathematics. A progression is a type of sequence for which a formula for the nth term can be found. The Arithmetic Progression is the most commonly used sequence in mathematics, with simple formulas.

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Answered by immishaan2002
0

Answer:

The final answer is 8 approx.

Step-by-step explanation:

We need to find out the average of the first 8 multiples of 2. Multiples are the numbers which are obtained by adding the same number several times. It can also be defined as let x be a number and y be another number. If x divides y then y is said to be a multiple of x.

The first 8 multiple of 2 are = 2

2 + 2 = 4

4 + 2 = 6

6 + 2 = 8

8 + 2 = 10

10 + 2 = 12

12 + 2 = 14

14 + 2 = 16

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 = 62

Sum of first 8 multiples of 2 = 62

Average of first multiples of 2 = 62 / 8 = 7.75 = 8 approx

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