Question

the average of the five consecutive even number is 42 .find the squre of the half value of the smallest num?

Answer 1

Given,

The average of 5 consecutive even numbers is 42.

To Find,

The square of half value of the smallest number.

Solution,

Let the five consecutive even numbers be x, x+2, x+4, x+6, x+8.

So,

(x+x+2+x+4+x+6+x+8)/5 = 42

5x+20 = 42*5

5x = 210-20

x = 38

So, 38 is the smallest number

Then, 38/2 = 19

19² = 361

Hence, the square of the half value of the smallest number is 361.