The average of the five consecutiven even num-
bers is 40. What is the value of smallest of these
numbers?
RRB NTPC 2016
(a) 35
(b) 36
(c) 44
(d) 46
10 heervations is 1 Two more
Answers
Answered by
0
Answer:
Answer is (b) 36
Step-by-step explanation:
if we take the set of five consecutive even numbers as x,x+2,x+4,x+6,x+8;
average=sum of the numbers ÷ total no. of numbers
average of five consecutive even numbers=
x+x+2+x+4+x+6+x+8 ÷ 5 =40
5x+20÷5=40
5x+20=40×5
5x+20=200
5x=200-20
5x=180
x=180÷5
x=36
then the sequence would be 36,38,40,42,44.
since 36 is the lowest among them,36 is the answer
Answered by
0
Answer:
(b) 36
Step-by-step explanation:
let numbers are n,n+2,n+4,n+6,n+8
sum of these numbers= n+n+2+n+4+n+6+n+8= 5n+20
no of numbers=5
average= sum /no of events
average= 5n+20/5= 40(given)
5n+20=200
5n=180
n=36 and it is smallest number
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