Question

The average of the four successive odd numbers 34 .What would be the value of the smallest of these numbers

Answer 1

SOLUTION:

four successive odd numbers

x,x+2,x+4,x+6 are 4 successive odd numbers

their average= (x+x+2+x+4+x+6)/4=34

4x+12=34×4

4x=124

x=31(smallest number)

CHECKING THE SOLUTION:

THE NUMBERS ARE 31,33,35,37

THEIR AVERAGE =(31+33+35+37)/4

=136/4

=34(HENCE EQUAL)

Answer 2

Given - The average of the four successive odd numbers 34.

Find - The value of the smallest of these numbers.

Solution - Let the very first odd number be X. The next three successive odd numbers will be X+2, X+4 and X+6 respectively.

Now, the question states that average of these numbers is 34. Therefore, (X + X + 2 + X + 4 + X + 6)/4 = 34.

Solving the equation-

(4x + 12)/4= 34

4x + 12 = 34*4

4x + 12 = 136

4x = 136 - 12

4x = 124

X = 124/4

X = 31.

So the numbers are - X = 31, X + 2 = 33, x + 4 = 35 and X + 6 = 37.

Hence, the value of smallest number is 31.