Question

the average of the four successive odd numbers is 34. what would be the value of the smallest of these numbers​

Answer 1

Given - The average of the four successive odd numbers 34.

Find - The value of the smallest of these numbers.

Solution - Let the very first odd number be X. So the next three successive odd numbers will be X+2, X+4 and X+6 respectively.

As per the question average of these successive odd numbers is 34. Therefore, (X + X + 2 + X + 4 + X + 6)/4 = 34.

Solving the equation-

(4x + 12)/4= 34

4x + 12 = 34*4

4x + 12 = 136

4x = 136 - 12

4x = 124

X = 124/4

X = 31.

So the numbers are - X = 31, X + 2 = 33, x + 4 = 35 and X + 6 = 37.

Hence, the value of smallest number in given numbers is 31.

Answer 2

SOLUTION

GIVEN

The average of the four successive odd numbers is 34.

TO DETERMINE

The value of the smallest of these numbers

CONCEPT TO BE IMPLEMENTED

A odd integer is of the form 2n - 1

EVALUATION

Let the four successive odd numbers are

2x - 1 , 2x + 1 , 2x + 3 , 2x + 5

Now sum of the four successive odd numbers

= 2x - 1 + 2x + 1 + 2x + 3 + 2x + 5

= 8x + 8

Again it is given that the average of the four successive odd numbers is 34

So sum of the numbers = 4 × 34 = 136

So by the given condition

8x + 8 = 136

$\implies \sf{8x = 128}$

$\implies \sf{x = 16}$

So the four successive odd numbers are 31 , 33 , 35 , 37

Hence the required smallest number = 31

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. The mean of 5 numbers is 39. If one number is excluded, their mean is 35, find the excluded number

https://brainly.in/question/33419522

2. The average age of A and B is 12 years, B and C is 9 years and that of C and Dis 23 years. If the average age of A,...

https://brainly.in/question/33842744