Question

The average of three consecutive even multiples of 9 is 72. What are these numbers?

Answer 1

Given,

The average of three consecutive multiples of $9$ is $72$.

Here we have to find out that three consecutive numbers.

Let the three consecutive numbers be $9x,9(x+2),9(x+4)$

We have multiplied each consecutive number with $9$, as given that numbers are multiples of $9$.

$\frac{9x+9(x+2)+9(x+4)}{3}=72$

$\frac{9x+9x+18+9x+36}{3}=72$

$9x+9x+9x+36+18=216$

$27x+54=216$

$27x=216-54$

$27x=162$

$x=\frac{162}{27}$

$x=6$

Substitute the value of $x$ in the consecutive numbers.

$9x=9(6)=54$

$9(x+2)=9(6+2)=9(8)=72$

$9(x+4)=9(6+4)=9(10)=90$

Therefore, the three consecutive even multiples of $9$ are $54,72,90$

Answer 2

Answer:

54,72,90

Step-by-step explanation: