Question

the average of three numbers is 32 the ratio between first and second number is 27:10 if the third number is 2 more than second number what is the sum of first and second number
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Answer 1

Answer:

x = 864/19

y = 320/19

z = 640/19

Step-by-step explanation:

Let the three numbers be x, y and z

(x+y+z)/3 = 32

x + y + z = 96.....equ 1

x : y = 27 : 10

x/y = 27/10

10x = 27y

x = 27y/10.....equ 2

z = 2y......equ 3

substitute equ 2 and equ 3 in equ 1

27y/10 + y + 2y = 96

(27y+10y+20y)/10 = 96

57y = 960

y = 960/57 = 320/19

y = 320/19

substitute y in equ 3

z = 2(320/19)

= 640/19

z = 640/19

substitute y in equ 2

x = 27(320/19) ÷ 10

x = 8640/190 = 864/19

x = 864/19

Verification:

x + y + z = 96

864/19 + 640/19 + 320/19 = 1824/19 = 96

Hence verified.

Hope it helps you:)