the average of two numbers is 64 .their difference is 66 .find the numbers
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Answered by
2
Let the numbers be a & b
(a+b)/2 = 64
a+b = 128
a = 128-b
a-b = 66
a = 66+b
_____________________
128-b = 66+b
2b = 62
b = 31
______________________
a = 66+b
a = 66+31
a = 97
========================
Hence the numbers are 31 & 97
(a+b)/2 = 64
a+b = 128
a = 128-b
a-b = 66
a = 66+b
_____________________
128-b = 66+b
2b = 62
b = 31
______________________
a = 66+b
a = 66+31
a = 97
========================
Hence the numbers are 31 & 97
Answered by
0
Let the two no. be a and b.
(a + b)/2 = 64
a + b = 128
a - b = 66
2a = 194
a = 97
and...
b = 128 - 97 = 31
a = 97 and b = 31
(a + b)/2 = 64
a + b = 128
a - b = 66
2a = 194
a = 97
and...
b = 128 - 97 = 31
a = 97 and b = 31
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