THE AVERAGE OF TWO NUMBERS IS SEVEN AND THREE TIMES THE
Answers
Answer:
(x + y)/2 = 7 <-----The average of two numbers is 7/
(x - y)*3 = 18 <-----Three times the difference between them is 18
Then:
(x + y)/2 = 7
x + y = 14
y = 14 - x, substitute this into (x - y)*3 = 18.
(x - (14 - x))*3 = 18
(x - 14 + x)*3 = 18
(2x - 14)*3 = 18
2x - 14 = 6
2x = 6 + 14
2x = 20
x = 10, plug this into (x + y)/2 = 7.
Then:
(10 + y)/2 = 7
10 + y = 14
y = 4
x = 10 y = 4
Step-by-step explanation:
the average of two numbers is 7, and three times the difference between them is 18. find the numbers
the average of two numbers is 7, and three times the difference between them is 18. find the numbers
(x + y)/2 = 7 <-----The average of two numbers is 7/
(x - y)*3 = 18 <-----Three times the difference between them is 18
Then:
(x + y)/2 = 7
x + y = 14
y = 14 - x, substitute this into (x - y)*3 = 18.
(x - (14 - x))*3 = 18
(x - 14 + x)*3 = 18
(2x - 14)*3 = 18
2x - 14 = 6
2x = 6 + 14
2x = 20
x = 10, plug this into (x + y)/2 = 7.
Then:
(10 + y)/2 = 7
10 + y = 14
y = 4
x = 10 y = 4