Question

The average of x, 3, (x-1), 5 and (2x-2) is 5, find the value of x.

Answer 1

$Given \: the \:average\: of\: x, 3, (x-1), 5 \:and\\ (2x-2) \:is\: 5$

$\boxed { \pink { Average = \frac{Sum \:of \:the \: terms }{Number \:of \: terms } }}$

$\implies \frac{x + 3 + (x-1) + 5+ (2x-2) }{5} = 5$

$\implies \frac{x + 3 + x-1 + 5+ 2x-2 }{5} = 5$

$\implies 4x + 5 = 5\times 5$

$\implies 4x = 25 - 5$

$\implies 4x = 20$

$\implies x = \frac{20}{4}$

$\implies x = 5$

Therefore.,

$\red{ Value \:of \:x } \green { = 5 }$

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Answer 2

${ \huge{ \bold{ \underline{ \underline{ \purple{Question:-}}}}}}$

The average of x, 3, (x-1), 5 and (2x-2) is 5, find the value of x.

______________________

${ \huge{ \bold{ \underline{ \underline{ \red{Answer:-}}}}}}$

✎Given :

$\implies\tt\bold{x, 3,x-1, 5\:and\:(2x-2)}$

$\implies\tt\bold{Average=5}$

✎Formula Used :

$\implies\tt\bold{{ \small{ \bold{ \bold{ \bold{ \green{Average=\dfrac{Sum\:of\:the\:terms}{Total\:No.\:of\:Terms}}}}}}}}$

✎Calculating :

$\implies\tt\bold{5=\dfrac{x+3+x-1+5+2x-2}{5}}$

$\implies\tt\bold{\dfrac{5}{1}=\dfrac{4x+5}{5}}$

$\implies\tt\bold{4x+5=5\times{5}}$

$\implies\tt\bold{4x+5=25}$

$\implies\tt\bold{4x=25-5}$

$\implies\tt\bold{4x=20}$

$\implies\tt\bold{x=\cancel\dfrac{20}{4}}$

$\implies\tt\bold{x=5}$

✔So, the value of x is 5 ..