English, asked by Dipuu982, 5 hours ago

The average power dissipated in 50 Ohm resistor is

Answers

Answered by IMNOTGENIUS2

0

Answer:

968 W

By Joules's Law, Power P=I

2 R

By Ohm's Law, V=IR

Hence, P=V

2 /R

P=968W

Explanation:

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