Question

The average power required to lift a 100 kg mass through a height

Answer 1

Explanation:

Mass = 100 kg

Height = 50 m

Time = 50 seconds

\textbf{Power = Change in P.E}Power = Change in P.E

P \: = \: \frac{mgh}{t}P=

t

mgh

P \: = \frac{100 \times 9.8 \times 50}{50}P=

50

100×9.8×50

P \: = 100 \times 9.8P=100×9.8

P \: = 980 \: WattP=980Watt

P \: = 980 \: J/sP=980J/s

Answer 2

Answer:

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