The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75 of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
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Step-by-step explanation:
Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
⇒ The cost of 2 books = Rs. 26
Let the price of each book be x and y.
⇒ x + y = 26 - - - - - - (1)
(160100)x+y=26
On Solving for y, we get
y = 10
Now, Substituting y = 10 in (1) we get,
x + 10 = 26
x = 16
So the price of each book is Rs. 16 and Rs. 10 respectively.
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