Question

The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?
A.Rs. 5, Rs.7.50
B.Rs. 8, Rs. 12
C.Rs. 16, Rs. 10
D.Rs. 12, Rs. 14

Answer 1

Answer:

10 AND 16

Step-by-step explanation:

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]

                                              = Rs. (120 - 94) = Rs. 26.

let the price of one book be Rs. x

Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x

So,  x+(8/5)x =26 <=> x =10

The prices of the two books are Rs. 10 and Rs. 16

Answer 2

The price of each of the other two books is C.Rs. 16, Rs. 10.

Given:

The average price of 10 books is Rs.12 while the average price of 8 of these books is Rs.11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other.

To Find:

The price of other two books.

Solution:

To find the price of the books we will follow the following steps:

As given in the question-

Total books = 10

The average price of 10 books = Rs. 12

The total price of 12 books = 12 × 10 = 120 Rs.

The average price of 8 books is Rs.11.75 which means the price of 8 books = 11.75 × 8 = 94Rs.

Price of the the the other two books will be -

Let the price of one of the two books = x

Now, the price of the second book is 60% more than the price of the first one.

So, the price of the second book =

$x + \frac{60}{100} x = x + 0.6x = 1.6 x$

The total price of books =

Price of 8 books + price of other two books = 120Rs.

94 + x + 1.6x = 120

2.6x = 26

$x = \frac{26}{2.6} = 10rs$

Price of another book = 1.6× 10 = 16Rs.

Henceforth, the price of each of the other two books is C.Rs. 16, Rs. 10.

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