Question

The average price of 16 apples is Rs. 32 while the average price of 14 of these apples is Rs. 22. Of the remaining two apples, if the price of one apple is 40% more than the other, what is the price of each of these two apples?

A) 125 & 89
B) 119 & 85
C) 133 & 95
D) 111 & 79​

Answer 1

Answer:

D 111&79 canal DC hc meko

Answer 2

$Given \: The \: average \: price \: of \: 16$

$apples \: is \: Rs\:32$

$\blue{ Cost\: of \: 16 \:apples } = 32 \times 16$

$= Rs \:512 \: --(1)$

$Given \: The \: average \: price \: of \: 14$

$apples \: is \: Rs\:22$

$\blue{ Cost\: of \: 14 \:apples } = 22 \times 14$

$= Rs \:308 \: --(2)$

$\green { Cost \: of \: remaining \: two \:apples }$

$= (1) - (2)$

$= Rs \: 512 - Rs\: 308$

$= Rs \: 204 \: --(3)$

$Let \: price \: of \: One \: apple = Rs \: x$

$Price \: of \: second \: apple = x\frac{ 100 + 40 }{100}$

$= x \times \frac{140}{100}$

$= \frac{7x}{5} \: --(4)$

$But \: (4) = (3)$

$\implies \frac{7x}{5} = 204$

$\implies x = 204 \times \frac{5}{7}$

$\implies x = Rs \: 85\: --(5)$

$Now, Second \: apple \: price = \frac{7x}{5}$

$= \frac{ 7 \times 85}{5}$

$= Rs \: 119\: --(6)$

Therefore.,

$Option \: \pink{ ( B) } \: is \: correct.$

•••♪