Math, asked by ankitpal059, 1 month ago

The average price of 80 mobile phones is
30,000. If the highest and lowest price
mobile phones are sold out, then the average
price of remaining 78 mobile phones is
29,500. The cost of the highest mobile is
80,000. The cost of lowest price mobile is:​

Answers

Answered by spnajyoti
0

Answer:

the average cost of two mobiles is 49500.

Answered by mathdude500
1

Question :-

  • The average price of 80 mobile phones is ₹ 30,000. If the highest and lowest price mobile phones are sold out, then the average price of remaining 78 mobile phones is ₹ 29,500. The cost of the highest mobile is ₹ 80,000. The cost of lowest price mobile is:

Answer :-

Given :-

  • The average price of 80 mobile phones is ₹ 30,000.
  • The average price of remaining 78 mobile phones is ₹ 29,500.
  • The cost of the highest mobile is ₹ 80,000.

To Find :-

  • The cost of lowest price mobile is:

Solution :-

The average price of 80 mobile phones is ₹ 30,000.

⇛ Price of 80 mobiles = 80 × 30, 000 = ₹ 24, 00, 000

Price of Highest mobile = ₹ 80000

Let Price of Lowest mobile = ₹ x.

After, selling mobile of lowest and highest price, the average price of remaining 78 is ₹ 29, 500.

Now, According to statement

80000 + x + 29, 500 × 78 = 24, 00, 000

⇛ 80000 + x + 23, 01, 000 = 24, 00, 000

⇛ x + 23, 81, 000 = 24, 00, 000

⇛ x = 19, 000

⇛ Lowest cost Price of mobile = ₹ 19, 000.

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