Question

the average price of three items of furniture is rupees 15000. If their prices are in the ratio 3:5:7, the price of the cheapest item is.

Answer 1

Given :

• The average price of three items of furniture is rupees 15000.

• Their prices are in the ratio 3:5:7.

To find :

• The price of the cheapest item =?

Step-by-step explanation :

Their prices are in the ratio 3:5:7. [Given]

Sum of the total Ratio = 3 + 5 + 7 = 15

Therefore, the sum of total ratio = 15.

The average price of three items of furniture is rupees 15000. [Given]

Now,

Cost of 1st item,

= 3/15 ×15000

= 3 × 1000

= 3000

Cost of 2nd item,

= 5/15 × 15000

= 5 × 1000

= 5000

Cost of 3rd item

= 7/15 × 15000

= 7 × 1000

= 7000

We can see that,

The cost of 1st item Rs. 3000 is the smallest price in the whole items cost. So, Rs. 3000 is the cheapest item.

Answer 2

ANSWER:

Price of the cheapest item : 3000 rupees.

GIVEN:

►The average price of three items of furniture : 15000 ruppes

►Prices of the items are in the ratio 3:5:7.

TO FIND:

The price of the cheapest item.

SOLUTION:

We are given,

►The average price of three items of furniture : 15000 ruppes

►Prices of the items are in the ratio 3:5:7.

⇨Sum of the total Ratio = 3 + 5 + 7 = 15

⛬ The sum of total ratio = 15.

The average price of three items of furniture is rupees 15000.

Now,

$\rm{cost \: of \: {1}^{st} \: item \: = \: \frac{3}{15} \times 15000}$

$\rm{cost \: of \: {1}^{st} \: item \: 3 \times 1000}$

$\rm{cost \: of \: {1}^{st} \: item \: = 3000}$

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$\rm{cost \: of \: {2}^{nd} \: item \: = \frac{5}{15} \times 15000}$

$\rm{cost \: of \: {2}^{nd} \: item = 5 \times 1000}$

$\rm{cost \: of \: {2}^{nd} \: item = 5000 \ ruppes}$

___________________________________

$</strong><strong>\</strong><strong>r</strong><strong>m</strong><strong>{</strong><strong>cost</strong><strong> \: of \: {3}^{rd} \: item = \frac{7}{15} \times 15000</strong><strong>}</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> </strong><strong>$

$</strong><strong>\</strong><strong>r</strong><strong>m</strong><strong>{</strong><strong>cost</strong><strong> \: of \: {3}^{rd} \: item \: 7 \times 1000</strong><strong>}</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> </strong><strong>$

$</strong><strong>\</strong><strong>r</strong><strong>m</strong><strong>{</strong><strong>cost</strong><strong> \: of \: {3}^{rd} \: item \: = 7000</strong><strong>}</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> </strong><strong>$

From above three prices we can say that ,

The price of first item is 3000 rupees . Which is smallest among all the three items .

Hence, price of cheapest item :3000 rupees