Question

The average salary of a company increases by 100 when the salary of the manager,
which is Rs. 9500, is included. If the number of employees excluding the manager is
the smallest cube divisible by 16, what is the final average of the company?
A Rs. 4000 B Rs. 3400 C Rs. 3700D Rs. 3100 E None of these​

Answer 1

Answer:

3100

Step-by-step explanation:

Smallest cube divisible by 16 is 4^3 =64

Therefore total employees excluding manager are 64

According to the question

Let A be the Average excluding the manager

9500 + 64(A) = (A+100)65

on solving above equation we get A= 3000

Thus final average = 3000+100 = 3100(including the manager)

Answer 2

Average

(D) 3100

Let the average salary before the manager's salary is included is $x$

After addition of Manager's salary , the average increases by $100$.

The smallest cube that is divisible by $16 \ is\ 64$.

Number of employees excluding will be  64, and total number including manager is 65.

According to question,

$64x + 9500 = 65 \times (x + 100)\\\\\implies 9500-6500=65x-64x\\\\\implies 3000=x$

 Hence , the average salary before the salary of manager is $Rs.\ 3000$.

Final average including manager's salary is $(3000+100)=Rs. 3100$.

Hence required average is 3100 option (d).