The average score by a person in 21 rounds of a game is 42. If in his 22nd game he scores "x" which increases his average score to 45. Find the value of "x".
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let he score in 21 round be y
42=y/21
y=882
he score in 22 round 882+x
so,
45=882+x/22
882+x=990
x=990-882
x=18
42=y/21
y=882
he score in 22 round 882+x
so,
45=882+x/22
882+x=990
x=990-882
x=18
ramya1318:
options are 1.63 2.45 3.42 4.108
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