Math, asked by sdev00277, 2 months ago

The average score of 70 students is 35. The average score of first 28 students is 53. Find the average of the remaining students
42
O 67
O 53
23
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Answers

Answered by nihanpreetkaur22
1

Answer:

let the no. of failed students= x

no. of passed students=75-x

avg. marks of students=35

total marks of students= 75*35=2625

avg. marks of failed students= 30

total marks of failed students=30x

avg. marks of passed students=55

total marks of passed students= 55*(75-x)

therefore,

30x+55(75-x)= 2625

30x+4125–55x= 2625

-25x = -1500

x = 60

Answered by swethassynergy
0

The average score of the remaining(42) students is 23 and option(4) is correct.

Step-by-step explanation:

Given:

The average score of 70 students is 35.

The average score of first 28 students is 53.

To Find:

The average score of the remaining students.

Solution:

As given- the average score of 70 students is 35.

The\ average\ score\ of\ 70\ students =\frac{Total\ score\ of\ 70\ students}{Nos.\ of\ students}

                                                   35 =\frac{Total\ score\ of\ 70\ students}{70}

Total\ score\ of\ 70\ students=35\times70 =2450

As given- the average score of 28 students is 53.

The\ average\ score\ of\ 28\ students =\frac{Total\ score\ of\ 28\ students}{Nos.\ of\ students}

                                                    53 =\frac{Total\ score\ of\ 28\ students}{28}

Total\ score\ of\ 28\ students=53 \times 28 =1484

The nos. of remaining students =70-28 students=42 students

Total score of 42 students=Total score of 70 students-Total score of 28 students

                                           =2450-1484=966

The\ average\ score\ of\ 42\ students =\frac{Total\ score\ of\ 42\ students}{Nos.\ of\ students}

                                                      =\frac{966}{42}\\=23

Thus, the average score of the remaining (42)students is 23 and option(4) is correct.

PROJECT CODE#SPJ2

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