Math, asked by kvsivasankar, 10 months ago

The average score of a cricketer for 10 matches is 38. If the average of the first 5 matches is 39, then what is the score in the last five matches?



Answers

Answered by adityamahale2003
1

Answer:

37

Step-by-step explanation:

Let average score of the last five matches=x

Then,

38 = (39+x)/2           [average here is of 2 observations]

76=39+x

x=37

Answered by empathictruro
0

Answer:

Score in last 5 matches=185

Average score=37

Step-by-step explanation:

Let consider matches a1, a2,. .. , a10

Given

(a1+a2+.. +a10) /10=38

(a1+a2+... +a10) = 380....(1)

(a1+a2+.. +a5) /5=39

(a1+a2+.. +a5) =195... . (2)

Sub (2) in (1)

195+a6+a7+..+a10=380

a6+a7+.. +a10=380-195=185

Totalscore in last 5 match=185

Their average score in last 5 matches=185/5=37

Similar questions