Question

The average score of John Harris after his 50th innings was 46.4. After 60th innings, John's average score increased by 26. What was John's average score in the last 10 innings? (A) 122 (B) 91 (C) 62 (D) 49​

Answer 1

Given : The average score of John Harris after his 50th innings was 46.4. After 60th innings, John's average score increased by 26.

To Find : What was John's average score in the last 10 innings?

(A) 122 (B) 91 (C) 62 (D) 49​

Solution:

The average score of John Harris after his 50th innings was 46.4.

=> Total score in 50 innings = 50 * 46.4

= 2320

After 60th innings, John's average score increased by 26.

New average = 46.4 + 26  = 72.4

Total score in 60 innings = 60 * 72.4

= 4344

Score in 10 innings  = 2024

Average score in 10 innings = 2024/10  = 202.4

if average score increased by 2.6

then 46.4 + 2.6 = 49

Total score in 60 innings = 60 * 49 = 2940

Score in 10 innings = 2940 - 2320

= 620

Average = 620/10  = 62

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Answer 2

Given:

The average score of John Harris after his 50th innings was 46.4. After the 60th innings, John's average score increased by 26. What was John's average score in the last 10 innings?

To find:

What was John's average score in the last 10 innings?

Solution:

To solve the above-given problem, we will use the following formula of the average:

$\boxed{\bold{Average = \frac{Sum \:of\:observations}{No. \:of\:observations} }}$

The average score of John Harris after his 50th innings was = 46.4

∴ The sum of scores of his 50 innings = 46.4 × 50 = 2320

After the 60th innings, the average of his score increases by 2.6

So, the average score of John's 60th innings = 2.6 + 46.4 = 49

∴ The sum of scores of his 60 innings = 49 × 60 = 2940

Therefore,

The sum of scores of the last 10 innings is,

= [Sum of 60 innings scores] - [Sum of 50 innings scores]

= 2940 - 2320

= 620

Now,

John's average score in the last 10 innings is,

= $\frac{620}{10}$

= $\bold{62}$

Thus, John's average score in the last 10 innings was → 62.

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