Math, asked by asantekofiisaac, 9 months ago

The average score of Josie had in 6 subjects is 72 and her average score after 2 additional subjects were added is 74.25. if she scored 80 in the 7th subject, what was her score in the 8th subject correct to the nearest whole number?

Answers

Answered by mddilshad11ab
74

\sf\large\underline{Given:}

  • \sf{The\: average\:score\:6\: subject=72}
  • \sf{The\: average\: score\:of\:8\: subject=74.25}
  • \sf{The\: scored\:in\:7th\: subject=80}

\sf\large\underline{To\: Find:}

  • \rm{The\: score\:in\:8th\: subject=?}

\sf\large\underline{Solution:}

  • At 1st calculate the total score in 6 subject after that we have to add the score of 2 additional subject]

\rm{\implies Total\: score\:in\:6\: subject=N\:of\:sub\times\: average\: score}

\rm{\implies Total\: score\:in\:6\: subject=6\times\:72}

\rm{\implies Total\: score\:in\:6\: subject=432}

\rm{\implies Let,\:The\: score\:of\:8th\: subject\:be\:x}

\sf\large\underline{Formula\:used}

\rm{\implies Average\: score=\dfrac{sum\:of\: score\:in\:all}{Number\:of\:all\: subject}}

\rm{\implies \dfrac{432+80+x}{8}=74.25}

\rm{\implies \dfrac{512+x}{8}=74.25}

\rm{\implies 512+x=74.25\times\:8}

\rm{\implies 512+x=594}

\rm{\implies x=594-512}

\rm{\implies x=82}

\sf\large{Hence,}

\rm{\implies The\: number\:of\: score\:in\:8th\: subject=82}

Answered by Anonymous
2

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