Question

the average speed of a cyclist who covers a first second and third km at 20,16 and 12km/ hr respectively in km/hr is​

Answer 1

Answer:

720/47 km/hr

Step-by-step explanation:

Let

S1=20km/hr , S2=16km/hr , S3=12km/hr

D1=D2=D3=1km

And time intervals be T1,T2,T3

As we know

             SPEED=  DISTANCE/ TIME

             TIME= DISTANCE/SPEED

therefor T1=1/20, T2=1/16, T3=1/12

WE KNOW

AVG SPEED = TOTAL DISTANCE/ TOTAL TIME TAKEN

                     =1+1+1/(1/20+1/16+1/12)

                     =3/(12+15+20)/240

                     =3.240/47

                     =720/47 km/hr

Answer 2

Answer:

Step-by-step explanation: