Question

The average speed of a train the onward journey is 25% more than that in the return journey. The train halts for 2hour on reaching the destination. The total time taken to complete to and for journey is 32hours,covering a distance of 1600km. Find the speed of the train in the onward journey is?​

Answer 1

Answer:

60 IND.

Step-by-step explanation:

distance/speed = time

S onward : S return = 125% : 100%

= 5 : 4

speed is inversely proportional to time so time ratio = 4 : 5

time taken to travel both sides

= 32 - 2 = 30 hrs

T onward = 4/9 * 30 = 13 1/3 = 40/3 hr

S onward = 800/40/3

= 2400/40 = 60 km/hr