Question

The average speed of an ideal gas molecule at 27°C is 0.3 m sec–1. Calculate average speed at 927°C.

Answer 1

Answer:

uav= √8RT / πM  

Given uav = 0.3 m sec–1 at 300K  

u1= 0.3 = √8R × 300 / πM  

at T = 273 + 927 = 1200K  

u2 = √8R × 1200 / πM  

u2 / 0.3 = √1200 / 300 u2 = 0.6 m sec–1

Answer 2

Answer:

0.6m/s

Explanation:

 

v1/v2=  √T1/T2

T1=27°C= 300K

T2=927°C=1200K

V1=0.3m/s

V2=√T2/T1 *V1= √1200/300 *0.3 = 0.6m/s