Question

The average temperature of a town in the first four days of a month was 58c. The average temperature for second, third, fourth and fifth days was 60c. If temperature on the first and fifth days was in the ratio 7:8, then what was the temperature on the fifth day

Answer 1

Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)

Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)

Subtracting (1) From (2), we get :

Temp, on 5th day - Temp on 1st day = 8 degrees.

Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.

Then, 8x - 7x = 8 or x = 8.

Temperature on the 5th day = 8x = 64 degrees.

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Answer 2

The temperature on the fifth day is 64 c.

Step-by-step explanation:

Since we have given that

Average temperature of a town in the first four days = 58 c.

Let the first four days are a,b,c,d.

So, it becomes,

$\dfrac{a+b+c+d}{4}=58\\\\a+b+c+d=232$ --------------------------(1)

Average temperature for second, third, fourth  and fifth days = 60 c.

So, it becomes,

$\dfrac{b+c+d+e}{4}=60\\\\b+c+d+e=60\times 4=240$ ---------------------------(2)

Since ratio of first and fifth days = 7:8.

So, from eq(1), we get that

$a+b+c+d=232\\\\b+c+d=232-a=232-7x$

Now, put in eq(2), we get that

$232-7x+8x=240\\\\x=240-232\\\\x=8$

Temperature on the fifth day would be

$8\times 8=64c$

Hence, the temperature on the fifth day is 64 c.

# learn more:

In winter the temperature of a place fell at the rate of 2/5 degrees per day if the temperature is 20 degrees on the first day what would be on the fifth day

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