the average temperature of a town in the first four days of a month was 58° and the average for 2nd 3rd 4th and 5th day was 66° if the temperature on the first and fifth were as 7:11 then the temperature on these days was?
Answers
Temperature on 1st day = 56° & Temperature on 5th day = 88°
Step-by-step explanation:
Let say Temperature on 1st Day = 7A° and 5th Day = 11A°
temperature on 2nd , 3rd & 4th Day = B° , C° , D° respectively
the average temperature of a town in the first four days of a month was 58°
=> (7A + B + C + D) /4 = 58
=> 7A + B + C + D = 232
=> B + C + D = 232 - 7A
the average for 2nd 3rd 4th and 5th day was 66°
=> (B + C + D + 11A)/4 = 66
=> B + C + D + 11A = 264
=> B + C + D = 264 - 11A
Equating
232 - 7A = 264 - 11A
=> 4A = 32
=> A = 8
Temperature on 1st day = 7A = 7*8 = 56°
Temperature on 5th day = 11A = 11*8 = 88°
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