Question

The average ticket price for a Spring Training baseball game is $32.10, with a standard deviation of $7.53. In a random sample of 40 Spring Training tickets, find the probability that the mean ticket price exceeds $34.,(Round your answer to three decimal places) Question Help: A Message instructor , solve for A

Answer 1

Answer:

etf

Step-by-step explanation:

Answer 2

The answer is 94.45%.

Given:

The average ticket price for a Spring Training baseball game is $32.10, with a standard deviation of $7.53.

A sample size of 40

To Find:

The probability that the mean ticket price exceeds $34

Solution:

We can solve this by finding the Z value of the sample, and then using the Z table to find the corresponding probability.

The z value is given by

$z =\sqrt n*\frac{x-\mu}{\lambda}$ where μ is the mean, n is the sample size, and λ is the standard deviation.

Here μ = 32.10, x = 7.53, n = 40, and λ = 7.53

Therefore

$z =\sqrt {40}*\frac{34-32.10}{7.53}\\\\z=1.596$

After corresponding to the z table, we get the value 0.9445.

Hence the probability is 94.45%.

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