Question

The average time that it takes for the car to travel the first 0.25m is s. The average time to travel just between 0.25 m and 0.50 m is s. Given the time taken to travel the second 0.25 m section, the velocity would be m/s.

Answer 1

Answer:

Explanation:

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

t=\frac{2.24s+2.21s+2.23s}{3}=2.227 s=2.23 s

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s =  0.92 s

So, the average time is

t=\frac{0.92 s + 0.87 s + 0.92 s}{3}=0.903 s=0.90 s

Answer 2

Answer:

1. 2.23

2. 0.90

3. 0.28

Explanation: