Question

The Average Translational Kinetic Energy Of 10 Gram H2 At 27 Degree Celsius Is _______.

Answer 1

Given :

T=27 Degree =273+27=300K

To find:

Average Translational Kinetic =?

Solution :

As we know that the average Translational Kinetic Energy can be determined by the

$E_{T} \ =\ \frac{3}{2}\ *KT$

Here T=300K

and k= $1.38* \ 10^{-3}$

Putting these value in the equation we get

$E_{T}\ =\ \frac{3}{2} \ * 1.38\ *10^{-3} \ * 300 \\E_{T}\ = 6.21\ * \ 10^{-21} \ j/molecule$