Question

the average value of current for the current shown for time period 0 to T/2​ is

Answer 1

Answer:

The average current will be given as

$i_{avg} = \frac{i_o}{2}$

Explanation:

As we know that average value of current is defined as

$i_{avg} = \frac{2}{T}\int_0^{T/2} i dt$

now we know that

$i_{avg} = \frac{2}{T}(Area)$

So here we can say that above integral is same as the area of the graph

So here we will have

$Area = \frac{1}{2}{\frac{T}{2}}{i_o}$

so the average current will be given as

$i_{avg} = \frac{i_o}{2}$

#Learn

Topic : Average current

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