Question

the average value of current for the current shown for time period 0 to T/2​ is

Answer 1

Explanation:

Answer:

The average current will be given asi_{avg} = \frac{i_o}{2}iavg=2io

Explanation:

As we know that average value of current is defined as

i_{avg} = \frac{2}{T}\int_0^{T/2} i dtiavg=T2∫0T/2idt

now we know that

i_{avg} = \frac{2}{T}(Area)iavg=T2(Area)

So here we can say that above integral is same as the area of the graph

So here we will have

Area = \frac{1}{2}{\frac{T}{2}}{i_o}Area=212Tio

so the average current will be given as

i_{avg} = \frac{i_o}{2}iavg=2io